Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:15Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

273K

d/dt [t^3] = 3t^2

263K

9r² + 4r + 1 = 0

E = mc²

139K

det| 9 4 ; 1 10 | = 86

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-α²) dα = √π / 2

333K

\lim_{t\to 0} \frac{\sin t}{t} = 1

160K

11γ² + 3γ + 6 = 0

F = ma

439K

∂γ/∂z = 6γ

413K

ΔS ≥ 0

297K

∑_{k=1}^{n} k = n(n+1)/2

128K

4γ² + 1γ + 7 = 0

404K