Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-05 19:39Z
∑_{k=1}^{n} k = n(n+1)/2
e^{i\pi} + 1 = 0
det| 5 6 ; 2 6 | = 18
373K
det| 3 7 ; 2 4 | = -2
172K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
341K
det| 7 8 ; 1 8 | = 48
∑_{k=1}^{n} k = n(n+1)/2
300K
1t² + 2t + 3 = 0
\frac{5}{1} \sum_{i=1}^{n} i^{2}
6n² + 9n + 5 = 0
\frac{7}{5} \sum_{i=1}^{n} i^{2}
∇ × E = −∂B/∂t
λ = h/p