Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-09-18 17:41Z

11t² + 4t + 5 = 0

∇²t = 0

171K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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E = mc²

det| 3 1 ; 7 4 | = 5

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det| 8 9 ; 4 9 | = 36

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det| 11 5 ; 5 12 | = 107

det| 10 7 ; 6 11 | = 68

1θ² + 2θ + 6 = 0

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CaCO₃ → CaO + CO₂

det| 11 4 ; 2 12 | = 124

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e^{i\pi} + 1 = 0

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d/dα [α^5] = 5α^4

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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iħ ∂ψ/∂t = Ĥψ

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∂r/∂y = 1r

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∇ × E = −∂B/∂t

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