Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-08-28 14:26Z

9n² + 2n + 1 = 0

det| 2 8 ; 7 3 | = -50

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

445K

F = ma

∇²β = 0

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d/dx [x^9] = 9x^8

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det| 5 1 ; 6 6 | = 24

∫₀^∞ e^(-t²) dt = √π / 2

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\frac{4}{6} \sum_{i=1}^{n} i^{2}

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N₂ + 3H₂ ⇌ 2NH₃

6t² + 6t + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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N₂ + 3H₂ ⇌ 2NH₃

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

466K

d/dφ [φ^1] = 1φ^0

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∇ × E = −∂B/∂t

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