Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-04 17:25Z
ω = 2πf
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 5 6 ; 2 6 | = 18
10K
det| 3 7 ; 2 4 | = -2
29K
∫₀^∞ e^(-z²) dz = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
90K
8ψ² + 3ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
34K
det| 2 6 ; 0 3 | = 6
8z² + 2z + 5 = 0
e^{i\pi} + 1 = 0
8ω² + 2ω + 0 = 0
iħ ∂ψ/∂t = Ĥψ
ΔS ≥ 0