Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-11 07:36Z
1φ² + 9φ + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 5 6 ; 2 6 | = 18
24K
det| 3 7 ; 2 4 | = -2
68K
5φ² + 4φ + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
257K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
217K
∂φ/∂n = 8φ
∇²φ = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇ × E = −∂B/∂t
\lim_{β\to 0} \frac{\sin β}{β} = 1
7n² + 6n + 7 = 0