Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-08-22 01:52Z
12α² + 1α + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
237K
det| 3 7 ; 2 4 | = -2
450K
det| 10 5 ; 4 11 | = 90
∑_{k=1}^{n} k = n(n+1)/2
473K
d/dy [y^8] = 8y^7
∑_{k=1}^{n} k = n(n+1)/2
118K
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
4z² + 8z + 1 = 0
det| 7 1 ; 3 8 | = 53