Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-09-20 08:30Z

12α² + 5α + 5 = 0

6ψ² + 5ψ + 4 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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ΔS ≥ 0

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12t² + 9t + 4 = 0

ΔS ≥ 0

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\oint_C \vec{F}\cdot d\vec{r} = 0

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det| 12 1 ; 5 13 | = 151

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iħ ∂ψ/∂t = Ĥψ

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CaCO₃ → CaO + CO₂

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3φ² + 5φ + 2 = 0

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det| 9 8 ; 3 10 | = 66

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1r² + 1r + 5 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\lim_{r\to 0} \frac{\sin r}{r} = 1

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