Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 23:38Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

12θ² + 2θ + 6 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

∑_{k=1}^{n} k = n(n+1)/2

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F = G m₁m₂ / r²

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ω = 2πf

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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E = mc²

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N₂ + 3H₂ ⇌ 2NH₃

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1θ² + 2θ + 6 = 0

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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∇ × E = −∂B/∂t

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det| 7 4 ; 4 8 | = 40

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7r² + 8r + 5 = 0

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