Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

∫₀^∞ e^(-θ²) dθ = √π / 2

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 4 7 ; 2 5 | = 6

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

N₂ + 3H₂ ⇌ 2NH₃

448K

det| 12 1 ; 5 13 | = 151

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

459K

6ω² + 4ω + 4 = 0

406K

∇ × E = −∂B/∂t

181K

∂z/∂φ = 7z

80K

8ψ² + 7ψ + 0 = 0

359K