Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 14:38Z

3γ² + 8γ + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

PV = nRT

∑_{k=1}^{n} k = n(n+1)/2

186K

det| 7 6 ; 1 8 | = 50

411K

det| 1 9 ; 5 2 | = -43

N₂ + 3H₂ ⇌ 2NH₃

448K

det| 7 4 ; 4 8 | = 40

22K

2n² + 4n + 0 = 0

459K

10γ² + 8γ + 7 = 0

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K