Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:47Z

10y² + 2y + 6 = 0

N₂ + 3H₂ ⇌ 2NH₃

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∑_{k=1}^{n} k = n(n+1)/2

438K

∫₀^∞ e^(-t²) dt = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

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det| 4 2 ; 6 5 | = 8

411K

e^{i\pi} + 1 = 0

\lim_{r\to 0} \frac{\sin r}{r} = 1

448K

CH₄ + 2O₂ → CO₂ + 2H₂O

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

459K

ω = 2πf

406K

∑_{k=1}^{n} k = n(n+1)/2

181K

CH₄ + 2O₂ → CO₂ + 2H₂O

80K

det| 7 4 ; 4 8 | = 40

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\lim_{β\to 0} \frac{\sin β}{β} = 1

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