Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 02:51Z
det| 5 4 ; 6 6 | = 6
det| 7 4 ; 4 8 | = 40
460K
∇²φ = 0
det| 4 8 ; 3 5 | = -4
411K
det| 12 5 ; 4 13 | = 136
det| 2 3 ; 5 3 | = -9
448K
CH₄ + 2O₂ → CO₂ + 2H₂O
22K
∑_{k=1}^{n} k = n(n+1)/2
det| 4 2 ; 6 5 | = 8
459K
∫₀^∞ e^(-α²) dα = √π / 2
406K
CaCO₃ → CaO + CO₂
∑_{k=1}^{n} k = n(n+1)/2
181K
E = mc²
ω = 2πf
CH₄ + 2O₂ → CO₂ + 2H₂O
det| 8 2 ; 1 9 | = 70
det| 8 1 ; 1 9 | = 71