Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:11Z

11n² + 5n + 4 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

∇ × E = −∂B/∂t

438K

∫₀^∞ e^(-x²) dx = √π / 2

∑_{k=1}^{n} k = n(n+1)/2

186K

N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

\frac{4}{9} \sum_{i=1}^{n} i^{2}

448K

e^{i\pi} + 1 = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

\lim_{t\to 0} \frac{\sin t}{t} = 1

459K

E = mc²

406K

d/dt [t^3] = 3t^2

181K

d/dx [x^9] = 9x^8

80K

PV = nRT

359K

8ψ² + 7ψ + 0 = 0

455K