Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:49Z

∇²n = 0

∇ × E = −∂B/∂t

273K

det| 4 8 ; 3 5 | = -4

263K

9r² + 4r + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

139K

∇²ω = 0

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

∫₀^∞ e^(-θ²) dθ = √π / 2

333K

d/dt [t^3] = 3t^2

160K

11γ² + 3γ + 6 = 0

6ω² + 4ω + 4 = 0

439K

d/dx [x^3] = 3x^2

413K

\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

8ψ² + 7ψ + 0 = 0

297K

10ω² + 7ω + 4 = 0

128K

det| 6 1 ; 3 7 | = 39