Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 20:35Z
det| 6 5 ; 4 7 | = 22
∇²φ = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
411K
\frac{9}{2} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
22K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
459K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
406K
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
455K
1φ² + 4φ + 5 = 0